World Maths Day Today

[Sunflower49]

Originally Posted by gpick24

I think you under estimate just how much you use things like algebra, most of us will use it on a regular basis.
A quick example -
You are in the pub, you have £20 to spend on drinks, drinks cost £4 each, how many drinks can you afford.

I would have said that is basic division-I may be mistaking what algebra actually is?

[Gordon Booth]

Originally Posted by gpick24

You are in the pub, you have £20 to spend on drinks, drinks cost £4 each, how many drinks can you afford.

None in that pub! Let's go somewhere else, unless you're paying.
Didn't take algebra to work that out.

[gpick24]

Originally Posted by sugarmouse0707

I would have said that is basic division-I may be mistaking what algebra actually is?

a=b X c
a=the £20 you have
b=£4 cost of drink/round
c=how many drinks/rounds can you have.

[gpick24]

Originally Posted by Gordon Booth

None in that pub! Let's go somewhere else, unless you're paying.
Didn't take algebra to work that out.

OK, i`ve already explained i may have the price wrong, lets change it to the cost of a round, how many rounds can you afford.

[Gordon Booth]

Originally Posted by sugarmouse0707

I would have said that is basic division-I may be mistaking what algebra actually is?

Originally Posted by gpick24

a=b X c
a=the £20 you have
b=£4 cost of drink
c=how many drinks can you have.

But c= a divided by b. So you're both right.

20 divided by 4= 5 is arithmetic.
a divided by b =c, values known and unknown, is algebra.

[Gordon Booth]

Originally Posted by gpick24

OK, i`ve already explained i may have the price wrong, lets change it to the cost of a round, how many rounds can you afford.

That's algebra because the value of b is unknown.So the value of c can't be calculated.

Let's keep it simple- you pay!

[gpick24]

Originally Posted by Gordon Booth

But c= a divided by b. So you're both right.

20 divided by 4= 5 is arithmetic.
a divided by b =c, values known and unknown, is algebra.

a=b X c
a is known, b is known, you want to know c.
So you divide both sides by c.
a/c=b X c / c
The X c/c cancel each other out and you get
a/c=b

[gpick24]

Sorry, didn`t mean to turn this thread into a maths lesson, just wanted to show most of us use things like algebra more than you think.

[Gordon Booth]

Originally Posted by gpick24

a=b X c
a is known, b is known, you want to know c.
So you divide both sides by c.
a/c=b X c / c
The X c/c cancel each other out and you get
a/c=b

How can I divide a by c when I don't know what c is?
The known on the left hand side, the unknown on the right hand side.
A/b=c

Originally Posted by gpick24

Sorry, didn`t mean to turn this thread into a maths lesson, just wanted to show most of us use things like algebra more than you think.

No problem, it's called thread wandering, you do it for fun. Sometimes it's surprising where you end up.

[gpick24]

Originally Posted by Gordon Booth

How can I divide a by c when I don't know what c is?
The known on the left hand side, the unknown on the right hand side.
A/b=c



No problem, it's called thread wandering, you do it for fun. Sometimes it's surprising where you end up.

[Gordon Booth]

Originally Posted by gpick24

At last! I'll have a pint, please.

[gpick24]

Originally Posted by gpick24

a=b X c
a is known, b is known, you want to know c.
So you divide both sides by c.
a/c=b X c / c
The X c/c cancel each other out and you get
a/c=b

Sorry, should have been divide both sides by b.
a/b=b X c / b
Multiplying by b then dividing by b cancel each other out.
a/b=c

[Gordon Booth]

Originally Posted by gpick24

Sorry, should have been divide both sides by b.
a/b=b X c / b
Multiplying by b then dividing by b cancel each other out.
a/b=c

Who cares? Just get that pint in, I'm dying of thirst!

[gpick24]

[MargaretR]

Originally Posted by gpick24

http://www.accringtonweb.com/forum/f...mer-29681.html

See rule 9 please